A magnetic field has a magnitude of 0.0818 T and is uniform over a circular surface whose radius is 0.174 m. The field is oriented at an angle of = 26.3o with respect to the normal to the surface. What is the magnetic flux through the surface?
Given :
Magnitude of magnetic field, B = 0.0818 T
Radius of circular surface, r = 0.174 m
Angle between magnetic field and circular surface, θ = 26.3o
Magnetic flux passing through any area is given by the relation:
Here A is area of the surface.
Area of the circular surface,A = πr2
Put this in equation (1).
Substitute the suitable values in the equation (2).
Magnetic flux passing through the surface is 6.97 x 10-3 T m2