Question

A point charge of -5 uC is located at x=4m, y=-2m. A second point charge of 12uC is located at x=1m, y=2m (a) Find the ...


A point charge of -5 uC is located at x=4m, y=-2m. A second point charge of 12uC is located at x=1m, y=2m

(a) Find the magnitude and direction of the electric field at x=-1m, y=0

(b) calculate the magnitude and direction of the force on an electron at x=-1m, y=0

Answer

Given,

q1=-5μC

q2=12 μC

a)

E1=14πε0q1r1pr1=(x=4,y=-2)p=(x=1,y=0)r1p=(4--1)2+(-2)2=3E1=9×109×-5×10-63=-15×103 r2p=(-1-1)2+(-2)2=2.83 mE2=9×109×12×10-62.83=38.162×103E=E1+E2=-15×103+38.162×103E=23.162×103 N/C

Direction of the Electric field is towards left.

b)

r1p=3 m

r2p=2.83 m

q=1.6×10-19 C

F1p=14πε0q1qr1p2F2p=14πε0q2qr2p2F=F1p+F2p=14πε0q1qr1p2+q2qr2p2=9×109-5×10-6×1.6×10-1932+12×10-6×1.6×10-192.832  =1.358×10-15 N

Using the parallelogram law the resultant force is in the direction of positive x axis.

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