Question

A 180-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping...


A 180-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.400 rev/s in 2.00 s? (State the magnitude of the force.)

Answer

Force required

τ=IαFr=IαF=Iαr=mr22ωtr=mrω2t

Substitute

F=180 kg1.50 m0.400 rev/s22.0 s2π rad1 rev=154 N

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