Question

Consider the following reaction where K. = 2.90x102 at 1150 K: 2 S03 (g)= 2 So2 (g) + 02 (g) A reaction mixture was foun...


Consider the following reaction where K. = 2.90x102 at 1150 K: 2 S03 (g)= 2 So2 (g) + 02 (g) A reaction mixture was found to contain 4.30×10-2 moles of SO, (g), 2.24×102 moles of SO, (g), and 4.45×102 moles of 02 (g), in a 1.00 liter container. Indicate True (I) or False (F) for each of the following: 1. In order to reach equilibrium S03(g) must be produced 2. In order to reach equilibrium K. must decrease 3. In order to reach equilibrium so, must be consumed 4. Q. is less than K.. 5. The reaction is at equilibrium. No further reaction will occur.
Transcribed: I Berry Cheesecake P.. A Macmillan Launchp... Antiscience Bellers J... I case studies brightspace P statlab 1-19, 25 [References] Use the References to access important values if needed for this question. Consider the following reaction where K. = 2.90x102 at 1150 K: 2 S03 (g) = 2 S02 (g) + 02 (g) A reaction mixture was found to contain 4.30×10-2 moles of SO3 (g), 2.24×10¯2 moles of SO, (g), and 4.45×102 moles of 02 (g), in a 1.00 liter container. Indicate True (T) or False (E) for each of the following: 1. In order to reach equilibrium S03(g) must be produced. v 2. In order to reach equilibrium K. must decrease. 3. In order to reach equilibrium So, must be consumed. 4. Q, is less than K.- 5. The reaction is at equilibrium. No further reaction will occur. ot Submit Answer Try Another Version 1 item attempt remaining pt pt 7:0 earch 23 (? 5/10

Answer

First we would Calculate value of reaction quotient ( Qc ) using given Concentrations of each molecule. 

Then we would compare it with Kc value as : 

1.) If , Kc = Qc ,then reaction is at Equilibrium. 

2.) If Qc > Kc , this means products are more , so reaction proceed in backward direction to consume products and produce reactants. 

3.) If , Qc < Kc , this means products are less , so reaction proceed in forward direction to produce products and consume reactants. 

Solution : 

Chemistry homework question answer, step 2, image 1

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