Question

If for a patient's lungs, the tidal volume is 410 ml, inspiratory capacity is 3050 ml, vital capacity is 3950 ml, total ...


7. If for a patient's lungs, the tidal volume is 410 ml, inspiratory capacity is 3050 ml, vital capacity is 3950 ml, total lung capacity is 4820 ml, find Inspiratory Reserve Volume, Expiratory Reserve Volume, Residual Volume, Function residual capacity. Express your answers in ml.

Answer

ANSWER;-

Inspiratory Reserve Volume=IC-TV

IC = inspiratory capacity ,TV = vital capacity

So; IRV = 3050-410= 2640ml

 Expiratory Reserve Volume ERV =VC-IC

VC(vital capacity)

so; ERV= 3950-3050=900ml

(RV) Residual Volume = TLC-VC = 4820-3950=870ml

 

 

 

 

(FRC) Function residual capacity = ERV+RV=900+870= 1770ml

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