Question

The magnitude of the magnetic flux through the surface of a circular plate is 2.50 10-5 T. m2 when it is placed in a reg...


The magnitude of the magnetic flux through the surface of a circular plate is 2.50 10-5 T. m2 when it is placed in a region of uniform magnetic field that is oriented at 46.0° to the vertical. The radius of the plate is 8.50 cm. Determine the strength of the magnetic field.
        mT?

Answer

magnetic flux = 2.5 *10-5  T m2Radius = 8.5 cm angle = 46 degree 

 

using formula , flux = BA cos(theta)2.5 * 10-5 = B*π(0.085)2 *cos 46oB = 1.585 *10-3 T B= 1.585 mT(magnetic field strength)

 

Recent Questions