Question

The magnitude of the magnetic flux through the surface of a circular plate is 2.50 10-5 T. m2 when it is placed in a reg...

The magnitude of the magnetic flux through the surface of a circular plate is 2.50 10^-5 T. m² when it is placed in a region of uniform magnetic field that is oriented at 46.0° to the vertical. The radius of the plate is 8.50 cm. Determine the strength of the magnetic field.
mT?

Science Physics Magnetic Effects of Current

Answer

Step #1 of 2

$m a g n e t i c f l u x = 2.5 * 10^{- 5} T m^{2} R a d i u s = 8.5 c m a n g l e = 46 d e g r e e$

Step #2 of 2

$u \sin g f o r m u l a, f l u x = B A \cos (t h e t a) 2.5 * 10^{- 5} = B * π {(0.085)}^{2} * \cos 46^{o} B = 1.585 * 10^{- 3} T B = 1.585 mT (magnetic field strength)$

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